DOOR HALF OPEN ALERT
hello friends today I am gonna telling you about some easy and valuable electronics projects for school and college practical
Have you ever accidentally left your front door half open and one of your pets or your little one ran away? Here is the smart solution to this problem. This circuit alerts you every ten seconds that your door is open.
The circuit is based on the popular 14 - stage ripple - carry binary counter IC CD4060 and a few discrete components. The counter built around IC CD4060 advances by one on the negative transition of each clock pulse. It is reset (which means all of its outputs go low) by applying a high pulse at its reset input pin 12 through switch S1 independent of clock. A normally - closed (N / C) push - to - off switch S1 is used as the door sensor
Working of the circuit is simple. When the door is closed , the switch S1 opens as per the mechanical arrangement and reset pin 12 goes high . The oscillator circuit built around resistor R2 and capacitor C2 stops oscillating Piezobuzzer PZ1 doesn't sound as out puts Q7 and 13 remain low
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| Fig1; circuit diagram |
when the door is opened , switch S1 closes and reset pin 12 goes low .The oscillator starts oscillating and after a short delay of about 10 seconds , the piezobuzzer ( PZ1 ) starts giving 10 - second long beeps every 10 seconds The beep duration of the buzzer can be varied by changing the values of timing components C2 or R2
Assemble the circuit on a general purpose PCB and enclose in a plastic cabinet . Mount the cabinet on the door frame and door switch S1 near the handle lock such that when the door is closed the switch (S1) opens. For powering the circuit, use an appropriate 3V battery pack.
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